Question

can anyone solve this problem please ​

Answer 1

Answer:

a-b+c =6 -------------(1). [Putting x=-1]

a+b+c =0-------------(2). [Putting x=1 ]

4a+2b+c=0----------(3). [Putting x=2 ]

Now, (2)+(1)= a+c=3

=> b=0-(a+c)=-3

Now, 4a+c=6 and a+c =3

Therefore, (4a+c)-(a+c)=6-3

=> 3a=3

=> a=1

So,c=0-(a+b)=0-(1-3)

=> c=2

Hence, a=1,b=-3,c=2. (Ans).