can anyone solve this problem please please please please please
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hey..!!!
find here ..!!!
factor of
x³-3x²-x+3
Solution :--
x³-3x²-x+3
=x³-x²-2x²+2x-3x+3
=x²(x-1)-2x(x-1)-3(x-1)
=(x²-2x-3)(x-1)
=[(x²-3x+x-3)](x-1)
=[x(x-3)+1(x-3)](x-1)
=[(x-3)(x+1)](x-1)
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