Question

can anyone solve this question?​

Answer 1

Answer:

$\alpha = \frac{d \omega}{dt} . \frac{d \theta}{d \theta} = \omega\frac{d \omega}{d { \theta}} \\ \\ \alpha \: d \theta = \omega \:d \omega \\ \int _{0} ^{6} \alpha \: d \theta = \int _{ \omega_{0} } ^{5 \omega_{0}}\omega \:d \omega \\ 6 \alpha = \frac{1}{2} ( {5}^{2} - {1}^{2} ) \omega_{0} {}^{2} \\ \alpha = 2 \omega {}^{2} _{0}$