Question

Can anyone solve this question

Answer 1

Ahoy !

let see this free body diagram :

here Block A - 
mass = m1 

here Block B - 
mass = m2 

Get full solution from Attachment .

#Riddle 
Answer 2 ......

Answer 2

see the figure 
   let the tension in the string is T. 
     when block  m₂ moves downward then frictional force act on block m₁ is left direction.
   e.g   T - fr = m₁a ______________(1)
        m₂g - T = m₂a __________________(2)
but we know ,
      frictional force = μ.normal reaction 
so, fr = μm₁g put it in equation (1) and solve both equations,
m₂g -μm₁g =(m₁ + m₂)a
       a  = (m₂ - μm₁)g/(m₁+m₂)   put this in equation (1) 
T -μm₁g = m₁.(m₂ - μm₁)g/(m₁+m₂) 
T = μm₁g +m₁.(m₂ - μm₁)g/(m₁+m₂) 
   =(μm₁² +μm₁m₂ +m₁m₂-μm₁²)g/(m₁ +m₂)
   =m₁m₂(1 + μ)g/(m₁ + m₂)

 hence option ( B)  is correct answer