Question

can anyone solve this question.​

Answer 1

$\mathcal \pink{{SOLUTION:-}} \\ \\ \\</p><p></p><p> </p><p> \tt \red{\frac{ {x}^{m + n} \times {x}^{n + 1} \times {x}^{1 + m} }{( {x}^{m} \times {x}^{n} \times x )^{2} } = LHS} \\ \\ \tt { \: = \: \: \frac{ {x}^{(m + n + n + 1 + 1 + m)} }{ {x}^{(2m + 2n + 2)} } } \\ \\ \tt { \: = \: \: \frac{ {x}^{(2m + 2n + 2)} }{ {x}^{(2m + 2n + 2)} } } \\ \\ \tt { \: = \: \: {x}^{2m + 2n + 2 - (2m + 2n + 2)} } \\ \\ \tt { \: = \: \: {x}^{2m + 2n + 2 - 2m - 2n - 2} } \\ \\ \tt \: = \: \: {x}^{0} \\ \\ \tt \: = \: \: 1 = RHS \\ \\ \tt \red{Hence \: \: verified \: \: that, \downarrow} \\ \\ \tt {\frac{ {x}^{m + n} \times {x}^{n + 1} \times {x}^{1 + m} }{( {x}^{m} \times {x}^{n} \times x )^{2} } \: \: = \: 1}$

Answer 2

here "^" this sign means raise to the power Or this sign"*"means multiplication

in first step we add the power of numerator because it is rule when base is some we can add power as:

x^ m+n+n+1+1+m divide by /( x^m)2 *(x^n)2*(x^1)2

Now ,when we add ,it becomes

x^2m+2n+2/x^2m*x^2n*x^2

x^2m+2n+2/ x^2m+2n+2

Now we take the denominator UPWARD ,its signs will be changed

x^2m+2n+2 -2m-2n-2

Now when we subtract them ,it becomes zero

x^0

when x raise to zero (x^0 ) ,it is equal to one

I make all my efforts to ans u and I provided u a picture of this answer also ,so please if u understand ,plz comment ,of u don't understand then also comment ,i will explain this agian