can anyone solve this question
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xy = 10^2 =100 (1)
log x/y + 2 log 2 = 2
log x/y + log 2^2 = 2
log x/y + log 4 = 2 (2)
We know,
log a +log b= log ab
Therefore,
log x/y + log 4 = log (4x/y)
From the equation (2),
log(4x/y) = 2
=> 4x/y = 10^2
=>4x/y= 100 (3)
Also from eq (1),
xy=100
=> 4x/y = xy
=> 4=y^2
=> y =2
Now xy =100
=> x = 100/y
=> x = 100/2 = 50
log x/y + 2 log 2 = 2
log x/y + log 2^2 = 2
log x/y + log 4 = 2 (2)
We know,
log a +log b= log ab
Therefore,
log x/y + log 4 = log (4x/y)
From the equation (2),
log(4x/y) = 2
=> 4x/y = 10^2
=>4x/y= 100 (3)
Also from eq (1),
xy=100
=> 4x/y = xy
=> 4=y^2
=> y =2
Now xy =100
=> x = 100/y
=> x = 100/2 = 50
Aishwarya3011:
If you would have told me properly, I would have edited my answer. You should not abuse someone who is helping you selflessly Sir.
after it one more eqation is there
You have disappointed me. I tried to answer as best as it was mentioned.
Is it my fault that you didn't mention the other equation?
log x/y +2log 2 =2
please solve it and give it to me
please verify if this is correct.
Is it correct?
And please do not abuse someone who tries to help you selflessly.
I hope this answer helps.
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