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A particle having initial velocity u moves with a constant acceleration a for a time t. Evaluate it for u=5m/s,a=2m/s and t=10s.
The distance travelled is given as,
s=ut+1/2at^2
s=5*10+1/2*2*10
s=60m
The final velocity is given as
v=u+at
v=5+2*10
v=25m/s
Hence distance travelled is 60m and final velocity is 25m/s.
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