can anyone solve this question ??
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From the question it is given that,
ξ = {natural numbers between 10 and 40}
ξ = {11,12, 13, 14, 15, …., 39}
ξ is a universal set and A and B are subsets of ξ.
Then, the elements of A and B are to be taken only from ξ.
A = {multiples of 5}
A = {15, 20, 25, 30, 35}
B = {multiples of 6}
B = {12, 18, 24, 30, 36}
(i) A ∪ B = {15, 20, 25, 30, 35, 40} ∪ {12, 18, 24, 30, 36}
A ∪ B = {15, 20, 25, 30, 35, 12, 18, 24, 36}
A ∩ B = {30}
(ii) n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
n(A ∪ B) = 5
n(A) = 5
n(B) = 5
n(A ∩ B) = 1
Then, n(A) + n(B) – n(A ∩ B) = 5 + 5 – 1 = 9
By comparing the results,
9 = 9
Therefore, n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
Step-by-step explanation:
Hope it helps :)
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