Can anyone solve this question?
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P stands for Perpendicular or altitude of triangle.
H stands for hypotenuse.
B stands for Base as a x.
"A" stands for theta
Value 1.
sin A =P/H
0.6 = 12/H
H = 12/0.6
H = 20 cm
By Pythagoras for base :
H² = P²+B²
B² = H² - P²
B² = 400-144
B= √ 256
B= 16 cm (it is x base)
I hope you like it☺️
P stands for Perpendicular or altitude of triangle.
H stands for hypotenuse.
B stands for Base as a x.
"A" stands for theta
Value 1.
sin A =P/H
0.6 = 12/H
H = 12/0.6
H = 20 cm
By Pythagoras for base :
H² = P²+B²
B² = H² - P²
B² = 400-144
B= √ 256
B= 16 cm (it is x base)
I hope you like it☺️
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dishankjaiswal3:
am feeling ashamed
I am not feeling good too.
angle theta = 0.6? how?
dishank it is sin theta = 0.6
angle theta is 36.86°
Yaaa...it shows that the ratio between the perpendicular and hypotenuse is 0.6
sin theta = 0.6?
please tell me i am unable to understand
see figure you understand well
sin theta is P/H
Answered by
3
By Pythagoras Theorem,
AB = √( x^2 + 12^2) = √( x^2 + 144) cm
Now,
Given, sin ¢ = 0.6
So, Perpendicular / Hypotenuse = 0.6
BC / AB = 0.6
12 / √( x^2 + 144 ) = 0.6
√( x^2 + 144 ) = 12 / 0.6
√( x^2 + 144 ) = 20
x^2 + 144 = 400.......square on both the sides.
x^2 = 400 - 144
x^2 = 256
x = 16 cm.............●
●●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
AB = √( x^2 + 12^2) = √( x^2 + 144) cm
Now,
Given, sin ¢ = 0.6
So, Perpendicular / Hypotenuse = 0.6
BC / AB = 0.6
12 / √( x^2 + 144 ) = 0.6
√( x^2 + 144 ) = 12 / 0.6
√( x^2 + 144 ) = 20
x^2 + 144 = 400.......square on both the sides.
x^2 = 400 - 144
x^2 = 256
x = 16 cm.............●
●●●●●●●●●●●●●●●●●●●●●
Hope it was helpful.
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