can anyone solve this question answer plzzz
Answers
Answer:
question no.(a) answer=
Step-by-step explanation:
The first step is to factor 392 (and hope that its factors are 2 and 7!).
392 = 2^3 * 7^2
Two useful basic properties of logarithms are:
log(ab) = log(a) + log(b)
log(a^k) = k log(a)
Accordingly,
log(392) = 3 log(2) + 2 log(7) = 3*h + 2*k
We also know that sqrt(392) = 392^(1/2). So log[sqrt(392)] = (1/2) * log(392) = (3/2)*h + k.
question no.2
answer =
We can write
4
1
3
in radical form, but not with square roots. We can write this using cube roots.
Here is a quick differentiation:
√
64
=
8
or
−
8
3
√
64
=
4
So, if we multiply
8
or
−
8
by itself, we get 64. If we multiply 4 by itself three times, we get 64. This same theory works with fraction exponents that get smaller (
x
1
4
,
x
1
5
,
x
1
6
).
Anything written to the
1
3
power is the cube root of that base number.
Given this, we can write:
4
1
3
=
3
√
4