Question

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Answer 1

Answer:

difference is 85cm³

Step-by-step explanation:

tin packs are two types in this problem.

case 1- cuboid shape

l=5cm;b=4cm;h=15cm

volume=lbh=5*4*15=20*15=300cm³

case 2- cylinder shape

d=7cm _r=3.5cm;h=10cm

volume=π²rh=22/7*3.5*3.5*10=11*35=385cm³

Answer 2

${\sf{\large{\pink{\bigstar{ \: Given:}}}}}$

We have given that soft drinks are available in two packs -

• A tin can with Height - 15 cm, Length - 5 cm, Width - 4 cm. It means that tin can is in the form of cuboid.

• Second is tin can of base diameter - 7 cm, height of 10cm. So, it means that tin can is in the form of Cylinder .

${\sf{\large{\pink{\bigstar{ \: To \: find:}}}}}$

• Which container has greater capacity and by how much.

${ \large{\sf{\red{\bigstar{ \: { \underline{ \underline{Solution:}}}}}}}}$

Here capacity can be also called as Volume.

(1)

So, Volume of Cuboid is :-

• Height - 15 cm
• Length - 5 cm
• Width - 4 cm

${\boxed{\underline{\green{ \sf{\star{Volume \: of \: cuboid = length × breadth × height}}}}}}$

${ \sf{Volume \: of \: cuboid = 5 × 4 × 15}}$

${ \underline{ \blue{ \sf{Volume \: of \: cuboid = 300 \: cm ^{3} }}}}$

So, Capacity or Volume of first tin can is 300 cm³.

(2)

So, Volume of Cylinder is :-

• diameter - 7 cm
• height = 10cm
• Radius = 7/2 = 3.5 cm

${\boxed{\underline{\green{ \sf{\star{Volume \: of \: cylinder= \pi {(r)}^{2}h }}}}}}$

${ \sf{Volume \: of \: cylinder= \frac{22}{7} \times {(3.5)}^{2} \times 10 }}$

${ \sf{Volume \: of \: cylinder= \frac{22}{7} \times 12.25\times 10 }}$

${ \sf{Volume \: of \: cylinder= 22 \times 1.75\times 10 }}$

${ \underline{ \blue{ \sf{Volume \: of \: cylinder = 385 \: {cm}^{3} }}}}$

So, capacity or volume of second tin can is 385 cm³.

Container which has greater capacity is :-

${\sf{\green{\underline{Greater \: Capacity =}}}} \\ { \sf{ \green{ Capacity \: of \: cylinder - \: Capacity \: of \: cuboid }}}$

${ \blue{ \underline{\sf{\implies{Greater \: Capacity = 85 cm³}}}}}$

So, Capacity of second tin is more than first tin can by 85 cm³.