Question

Can anyone solve this step by step...... ​

Answer 1

Answer:

bro UR answer

by theorem ,

Angle AOB = ANGLE ACB / 2 = 40/2 = 20°

Step-by-step explanation:

IN ∆ AOB,

AO = BO = RADIUS

SO, ∆ AOB IS AN ISOCELES TRIANGLE

ANGLE OAB = ANGLE OBA

USING ANGLE SUM PROPERTY →

O + A + B = 180°

2A + O = 180°

2A = 180° - 20°

2A = 160°

SO,

ANGLE OAB = 80°

MARK AS BRAINLIST IF POSSIBLE!!

Answer 2

Step-by-step explanation:

pls mark it as the brainliest answer....

have a bright future ahead....

thanks....