can anyone solve this.U can do anyone among these.Please solve this
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for question 37...
answer will be in this form only unless some values are not given(>ω<)
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for 37
sinA=cosA means
A=45°
then 2(tanA)^2+ (sinA)^2-1
2(1)^2+(1/√2)^2-1
2+1/2-1
=3/2
for 38
5sinA=12 cosA
gives sinA/cosA=12/5
tanA=12/5
then
sinA+cosA=tanA+1 =12/5 +1=17/5 (when divided by cosA)
and 2cosA-sinA=2-tanA= 2-12/5 =-2/5
answer is17/-2=-17/2
for 39
Theta=45°
and pi=15°
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