Can anyone solve this
Will be the most kind person..
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given CG = GB
angleC=angleB
angleDGC=angleAGB
Hence,
∆DGC congruent to ∆AGB
So,
AG=DG
angleC=angleB
angleDGC=angleAGB
Hence,
∆DGC congruent to ∆AGB
So,
AG=DG
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