Question

Can anyone solve this with some easy method?​

Answer 1

Answer:

yes i will slove it for u in easy method ok

Step-by-step explanation:

To prove : Plies on the circumcircle of the triangle.

Proof.

< BAP = < CAP ,

=> chord BP = chord CP

=> BP= CP

In triangle BMP and triangle CMP,

BM=CM[M is the bisector of BC]

BP=CP [Proved above]

MP=MP[Common side]

.

. . triangle BMP =~ triangle CMP[SSS]

.

. . < BMP =< CMP [CPCT]

BUT<BMP+<CMP = 180 degree [linear pair]

.

. . <BMP=<CMP=90 dergee

PM is the right bisector of BC.

HOPE THIS ANSWER WILL HELP U

SO PLZZ MARK ME AS BRANLIEST.... PLZ

Answer 2

Answer:

Because this can also make him leave the group