Can anyone solve this...WITH steps.
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when we see 1 and 3 condition then we came to know that 2,4,6 and 8 can't be the digits.
hence 5 and 7 are two correct digits.
Now according to last condition when we see we get 7 placed at right position and we also get one more correct digit i.e. 9 ( 1 can't be correct bcoz in 3 condition only one correct digit is available and that is 5).
so we have 3 correct digits and they are 5, 7, and 9 and all other given numbers cdon't satisfy the conditions so 4th number could be 3 which is not given in any condition.
So four correct digits are 3,5,7 and 9.
Now after satisfying all conditions we get the code:
3759 or 5739.
hence 5 and 7 are two correct digits.
Now according to last condition when we see we get 7 placed at right position and we also get one more correct digit i.e. 9 ( 1 can't be correct bcoz in 3 condition only one correct digit is available and that is 5).
so we have 3 correct digits and they are 5, 7, and 9 and all other given numbers cdon't satisfy the conditions so 4th number could be 3 which is not given in any condition.
So four correct digits are 3,5,7 and 9.
Now after satisfying all conditions we get the code:
3759 or 5739.
Sunandit:
and both of the proposed codes satisfy the conditions
Thanks a lot...and the correct answer is 5739...according to the first clue...5 in third position is incorrect
kk
oh yes!! i forgot about it pratit!!
Alrighty
^_^
hii sunandit
hiiiiii
r u sunandit?
yup
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