Question

Can anyone solve this x/3+1=7/15find the value of x.​

Answer 1

Answer:-

$\sf{} x=-\dfrac{8}{5}$

Let's solve your equation step-by-step.

$\rightarrow \sf{\dfrac{x}{3}+1=\dfrac{7}{15}}$

$\rightarrow \sf{}\dfrac{x}{3}=\dfrac{7}{15}-1$

LCM of 15 and 1 = 15

$\rightarrow \sf{}\dfrac{x}{3}=\dfrac{7\times1-1\times15}{15}$

$\rightarrow \sf{}\dfrac{x}{3}=\dfrac{7-15}{15}$

$\rightarrow \sf{}\dfrac{x}{3}=-\dfrac{8}{15}$

$\rightarrow \sf{}x=-\dfrac{8}{15}\times3$

$\rightarrow \sf{}x=-\dfrac{8}{5}$

$\sf{}Hence,x =-\dfrac{8}{5}$

☆ Additional Information ☆

Equation:-

• An equation says that two things are equal.

• It will have an equals sign "=" like this:

6 + 6 = 48 - 36

Answer 2

Let's solve your equation step-by-step.

$\frac{x}{3}+1=\frac{7}{15}$

Step 1: Simplify both sides of the equation.

$\frac{1}{3}x+1=\frac{7}{15}$

Step 2: Subtract 1 from both sides.

$\frac{1}{3}x+1-1=\frac{7}{15}-1$

$\frac{1}{3}x=\frac{-8}{15}$

Step 3: Multiply both sides by 3.

$3\times \frac{1}{3}x=3\times \frac{-8}{15}$

$x=\frac{-8}{5}$

∴$x=\frac{-8}{5}$ in the equation ⇒ $\frac{x}{3}+1=\frac{7}{15}$

Additional Information

Algebra is all about puzzles. Here, $\sf x+6=13$ we simply need to find the value of 'x'. So here 'x' is equal to 7. We can say that the sum of 7 and 6 is 13. Over here 'x' is a variable.

Variable is an unknown value and is mostly represented in small alphabets.

Constant is a number that has a proper value.

In an algebraic expression, we don't have an equal sign whereas, in an algebraic equation, we have an equal sign.