Question

can anyone solve thissss​

Answer 1

your answer is attached above

hope it helps u..

Answer 2

Answer:

The value of x are 2 and 3.

Step-by-step explanation:

Solve the equation for x as follows:

$log_{a}a^{x^{2}-5x+8}=2$

$(x^{2}-5x+8)\times log_{a}a=2$

$(x^{2}-5x+8)=2\\x^{2}-5x+6=0\\x^{2}-3x-2x+6=0\\x(x-3)-2(x-3)=0\\(x-3)(x-2)=0$

If (x - 3) = 0, then the value of x is 3.

If (x - 2) = 0, then the value of x is 2.

Thus, the value of x are 2 and 3.