Question

can anyone tell how to calculate or find oxidation number... plz explain with example.. ​

Answer 1

Explanation:

H2SO4

find the oxidation no of S

here we know that

valency of H2 is 1

no of H atoms=2

Oxidation no of H2 for the given compound=2*1

Oxidation no of S be x

valency of O is -2

no of O atoms =4

oxidation no of O= -2*4=-8

now

if as here is no charge on the compound

sum of all must equal to 0

therefore

2+x-8=0

x=6

Answer 2

Explanation:

oxidation no of O is -2 you have to remember oxidation no of few elements