can anyone tell me how to solve this questions
1. Determine if ( X + 1) is a factor of x3 + x2 + X + 1
x2=xsquare
x3=xcube
2.find that (2,3) is a solution of the equation 2x+3y=5
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Answer:
Step-by-step explanation:
Divide the polynomial by given factor.
(X³ + x² + x + 1) ÷ (x+1) = x² + 1
Therefore, x+1 is a factor of the given polynomial.
2. Put x = 2 and y = 3
Therefore, 4+9 ≠ 5.
Therefore,(2,3) is not a solution of given equation.
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