Math, asked by arnavsingh2905p85e2p, 1 year ago

can anyone tell me question 14

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Answered by ilaashukl
1

Since we are working for %, we can assume some value for the initial alloy..

So let's take it 100 and B:G:S is 90:7:3

Now another alloy, A, is added to it and gold becomes 5% BUT the gold is not added at all..

So 7 becomes 5% of new total . .......5% of total = 7.... total = 7*100/5=140

Thus new alloy,A, added = 140-100=40

Now let's concentrate on the bronze..

Bronze is 85% of new total = 140*85/100=119

So increase in bronze=119-90=29=quantity of bronze in new alloy,A.

So % of bronze in A=100*29/40=72.5%


Answer: B


arnavsingh2905p85e2p: thank you
ilaashukl: Welcome
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