can anyone tell me the answer of the above attached question, okz be honest
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Answer:
d is the correct answer
Explanation:
in a concave mirror
u<f = virtual and enlarged image
u > f = either the image will be too small (at infinity) or it is real and enlarged
f<u<2f = it means object is placed between C and F so image will be beyond Means real and enlarged
u >2f = it will form a diminished image
in a convex mirror
u <f = we will get a virtual and small image
please mark the brainliest
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