Question

Can anyone tell me the answer of this question.....It's urgent...Please​

Answer 1

Given,

$\displaystyle\longrightarrow\sf{2^{x-y}=2^{x+y}=2^{\frac {3}{2}}}$

But we just consider,

$\displaystyle\longrightarrow\sf{2^{x-y}=2^{x+y}}$

Since base is same in both (i.e., 2), the exponents can be equated.

$\displaystyle\longrightarrow\sf{x-y=x+y}$

Subtracting $\displaystyle\sf {x,}$

$\displaystyle\longrightarrow\sf{-y=y}$

Adding $\displaystyle\sf {y,}$

$\displaystyle\longrightarrow\sf{-y+y=y+y}$

$\displaystyle\longrightarrow\sf{2y=0}$

$\displaystyle\longrightarrow\underline {\underline {\sf{y=0}}}$

Hence 0 is the answer.