Question

Can anyone tell me the SOLUTION of this question…
Please

Answer 1

Answer:

option A 7/8

Probability of having at least one boy is 7/8

hope it's help full Army

Answer 2

${\underline{\sf \green{Answer:-}} }$

a)

$\sf \frac{7}{8}$

${\underline{\sf \green{Explaination:-}} }$

In a family of 3 children, to find the probability of having at least 1 boy, let us find the probability of no boy.

In a family of 3 children, to find the probability of having at least 1 boy, let us find the probability of no boy.The sample space for different cases contains

$\sf {2}^{3}$

=8 points. [ As there are 3 children and the child may be boy or a girl] among which there is only one case when there are all girls that means no boy.

=8 points. [ As there are 3 children and the child may be boy or a girl] among which there is only one case when there are all girls that means no boy.So probability of no boy is

$\sf \: \frac{1}{8}$

So the probability of at least one boy is

$\sf \: 1 - \frac{1}{8}$

$\sf = > \frac{7}{8}$