can anyone tell me the test of divisibility of 11
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Answer:
For a number divisible by 11.
let the number be 121 let another number be 132
1st digit =1 1st digit=1
2nd digit=2 2nd digit= 3
3rd digit=1 3rd digit =2
Then, then
(1st + 3rd)-2nd (1+2)-3
=(1+1)-2 =3-3
=2-2 =0
=0
If we get 0 or 11 at the last step then the number is divisible by 3.
Hope it helps!
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