can anyone tell me thestructure of [Cr(O2)(NH3)4(H2O)]Cl2 ???
& here oxidation number of Cr is +3, then O2 will be in which form?? options are
a. dioxo
b. peroxo
c. superoxo
d. Oxo
Answers
Answered by
18
in your question you have written that oxidation no. of Cr is +3. NH3=0 because it is a neutral compound. H2O has also 0 oxidation no. Cl= -1.
so. if we calculate the oxidation no. of O2 then it will be -1.
so. if we calculate the oxidation no. of O2 then it will be -1.
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Answered by
1
Answer:
answer is superperoxo
reason: the oxidation state of oxygen (O) here is -1/2 or O2 is -1.
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