can anyone tell me this ans tomorrow is my exam plssssss
Answers
Dear friend,
The garden is made up of a rectangle and two semi-circles.
First we have to find the area of the rectangle,
= Length × Breadth
= [20-2(3.5)] × 7 m^2
= [20-7] × 7 m^2
= 13 × 7 m^2
= 91 m^2
Then area of the two semi-circles,
Radius = 7÷2 = 3.5
= 1/2×π×(r)^2
= 1/2×22/7×(3.5)^2
= 19.25 m^2
= 19.25 × 2 m^2
= 38.5 m^2
Total area = 91 + 38.5 m^2 = 129.5 m^2
Now total perimeter,
= 2(length + πr)
= 2(13 + π3.5)
= 2(13 + 22/7×3.5)
= 2(13 + 11)
= 2×24
= 48 m
Answer:
(i) Total area of park = 129.5 m^2
(ii) Total perimeter of park = 48 m
Hope it helps !!!
area of rectangular shape = length × breadth
length = [20-(3.5+3.5)]m , breadth = 7m
area = 20-(3.5+3.5) × 7 m²
area = 20-7 × 7 m²
area = 13 × 7 m²
area = 91m²-----------------------(1)
Now area of two semi circles = ½πr²
r = 7/2m
area = (1/2 × 22/7 × 7/2 × 7/2)2
area = (1/2 × 11 × 7/2)2
area = (7/4×11)2
area = (77/4)2
area = (19.25)2
area = 38.5m²---------------------(2)
area of garden is equation--(1) + equation--(2)
area of garden = 91m²+38.5m²
area of garden = 129.5m²
perimeter of garden = 2(length+πr)
perimeter = 2(13+22/7×3.5)
perimeter = 2(13+11)
perimeter = 2(24)
perimeter = 48m²