Question

can anyone tell me this answer​

Answer 1

$\boxed{Answer\:=>\:43}$

$\bold{Given,}$

$\bold{Arithemetic\:mean\:of\:9\:observations\:=\:38}$

$\bold{While\:calculating\:27\:is\:written\:instead\:of\:72}$

$\bold{Mean=38\:,No\:of\:observations=9}$

$\bold{To\:find\:the\:sum\:of\:observations\:=>}$

$\bold{=\:38\times9}$

$\bold{Sum\:of\:the\:observations=342}$

$\bold{[Subtract\:27\:from\:the\:sum\:of\:observations]}$

$\bold{=\:342-27}$

$\bold{=\:315}$

$\bold{[Add\:72\:]}$

$\bold{=\:315+72}$

$\bold{=\:387}$

$\bold{New\:mean\:of\:the\:data\:=>}$

$\bold{mean \: = > \: \frac{sum \: of \: observations}{no \: of \: observations}}$

$\bold{mean \: = > \: \frac{387}{9}}$

$\bold{New\:mean\:=>\:43}$

Answer 2

ANSWER:-----

Arithmetic mean of conservation's=38

While calculating 27 is written instea 72\bold{While\:calculating\:27\:is\:written\:instead\:of\:72}Whilecalculating27iswritteninsteadof72

Mean=38,Noofobservations=9\bold{Mean=38\:,No\:of\:observations=9}Mean=38,Noofobservations=9

Tofindthesumofobservations=>\bold{To\:find\:the\:sum\:of\:observations\:=>}Tofindthesumofobservations=>

=38×9\bold{=\:38\times9}=38×9

Sumoftheobservations=342\bold{Sum\:of\:the\:observations=342}Sumoftheobservations=342

[Subtract27fromthesumofobservations]\bold{[Subtract\:27\:from\:the\:sum\:of\:observations]}[Subtract27fromthesumofobservations]

=342−27\bold{=\:342-27}=342−27

=315\bold{=\:315}=315

[Add72]\bold{[Add\:72\:]}[Add72]

=315+72\bold{=\:315+72}=315+72

=387\bold{=\:387}=387

Newmeanofthedata=>\bold{New\:mean\:of\:the\:data\:=>}Newmeanofthedata=>

mean=>sumofobservationsnoofobservations\bold{mean \: = > \: \frac{sum \: of \: observations}{no \: of \: observations}}mean=>noofobservationssumofobservations

mean=>3879\bold{mean \: = > \: \frac{387}{9}}mean=>9387

Newmean=>43\bold{New\:mean\:=>\:43}Newmean=>43

hope it helps:-------

T!—!ANKS!!!