Question

can anyone tell the angles with valid reasons(properties)

Answer 1

Let AC and BD intersex at Our

∆AOD is congruent to∆ BOC (A.A.S)

=>AO=BO and DO =CO (c.p.ct)

Angle CAB=DBA =30°

In∆BAC

(Ii) =>angle BCA=180-(30+30+70)=50°

(Iii)=> And angle ABC=30+30=60°

Also,angle BAC=angle BDC =30°

(angle subtended by same arc)

In∆BCD,70+30+angle BCD=180°

(I). =>Angle BCD=80°

Angle ADB=angle ACB=50°(angle

subtended by same arc)

Hope it helps.