Question

Can anyone tell the answer for this?i solved it but idk if it’s correct ...thanks

Answer 1

Answer:

Explanation:

USUALLY WE TAKE THE INITIAL DIRECTION OF MOTION OF THE BODY AS POSITIVE, AND THE DIRECTION OPPOSITE TO IT AS NEGATIVE DISTANCE MOVED=1.29M

INITIAL SPEED=?

WHEN HE REACHES 1.29M ,HE COMES TO REST HENCE FINAL VELOCITY=0

G=-10[ TAKEN NEGATIVE ,ACTS OPPOSITE TO THE DIRECTION OF INITIAL MOVT OF THE BODY.]

V²-U²=2AS

0-U²=2*-10*1.29

U²=2*12.9

U²=25.8

U=5.07MS^-1

TIME TAKEN TO MOVE UPWARD=T1

V=U+AT1

0=5.07-10*T1

10T1=5.07

T1=0.507S

TIME TAKEN TO MOVE DOWNWARDS=T2

[WHEN STARTS FROM TOP IT'S INITIAL VELOCITY IS 0 ]

S=UT+0.5AT2²

1.29=0+0.5*10*T2²

1.29=5T2²

T2=0.507S

TOTAL TIME TAKEN=1.014S

HOPE IT HELPS.