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Let A be the set of families which buy newspaper A, B be the set of families which buy newspaper B and C be the set of families which buy newspaper C.
Number of families=10000
n(A)= 40× 10000
_______ = 4000
100
n(B)= 20× 1000
_______ = 2000
100
n(C)= 10× 10000
______ = 1000
100
n(A∩B)= 4× 10000
_________ = 400
100
n(B∩C)= 3× 10000
_______ = 300
100
n(A∩B∩C)= 2× 10000
________ = 200
100
no. of people buy only A, only B & only C=1400+200+3300=4900
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