Question

Can Cancer patient survive if it's little late? I mean by operation?​

Answer 1

Answer:

Required Answer:-

We have:

The ratio of the present ages of a mother and her

daughter is 7 : 1

Four years ago, the ratio of their ages was 19 : 1.

To FinD:

What will be the mother's age four years from now?

Step-by-Step Explanation:

Let the ages of mother and daughter be x and y respectively.

According to condition -(1)

➛ x : y = 7 : 1

By the principle of proportion, Product of means = Product of extremes.

➛ x = 7y --------(1)

According to condition -(2)

➛ x - 4 : y - 4 = 19 : 1

Again by the principle of proportion, Product of means = Product of extremes.

➛ x - 4 = 19(y - 4)

➛ x - 4 = 19y - 76

➛ x - 19y = -72 ------(2)

Substituting x = 7y in equation (2),

➛ 7y - 19y = -72

➛ -12y = -72

➛ y = 6

Then, x = 42

Therefore:-

The age of the mother after 4 years will be 42 + 4 = \boxed{\bf{46 \:years}}

46years

Answer 2

Those diagnosed in stage 4 who decide against treatment live an average of 6 months. Researchers use tumor grading to estimate how fast a tumor may grow. Cell abnormalities and how rapidly the cancer cells are dividing play a role in overall tumor growth. These factors are associated with survival.