Can every positive integer be represented as 4x+2 (ℎ x )?
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Answer:
The answer is -500
We have to put x=12 in the given equation .
h(12) = -5 (12-2)^2:
using identity (a-b)^2 = a^2+b^2-2ab
= -5 {(12)^2+(2)^2+2×12×2}
= -5 ( 12×12+2×2-2×12×2)
= -5 (144+4-48)
= -5 (148-48)
= -5 ×100
= -500
Hence ,
h(12)= -500
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