Question

Can fuo numbers have 16 as their HCF and 204 as thetr LCM? Glue red
We know that the HCF of two or more numbers must divide their LOM
Souton
4. 36, 60,72
8. 144.180,3
Mathematics for Clasa 6
19. The HCF of two numbers is 145 and their LCM is 2175. If one of the numbers is 72%
20. The HCF and LCM of two numbers are 131 and 8253 respectively. If one of the num
22. Find the least number which when divided by 25, 40 and 60 leaves 9 as the remaine
We know that
(one number) x (the other number) = (HCF X LCM).
Hence, the required number =
23 1449
161
- 207
EXAMPLE 10
Solution
But, 16 does not divide 204 exactly
So, there can be no two numbers with 16 as their HCF and 204 as the
EXERCISE 2E
Find the LCM of the numbers given below:
1. 42. 63
2. 60, 75
3. 12, 18, 20
5. 36, 40, 126
6. 16. 28, 40, 77 7. 28, 36, 45, 60
48. 64, 72, 96, 108
Find the HCF and LCM of
10. 117, 221
11. 234, 572
12. 693, 1078
14. 861, 1353
15. 2923, 3239
16. For each pair of numbers, verify that their product (HCF X LCM).
(1) 87, 145
(ii) 186, 403
(ii) 490, 1155
17. The product of two numbers is 2160 and their HCF is 12. Find their LCM.
18. The product of two numbers is 2560 and their LCM is 320. Find their HCF.
the other.
917, find the other.
21. Find the least number divisible by 15, 20, 24, 32 and 36.
1353
13. 145, 232
each case.
23. Find the least number of five digits that is exactly divisible by 16, 18, 24 and 30.
24. Find the greatest number of five digits exactly divisible by 9, 12, 15, 18 and 24
25. Three bells toll at intervals of 9, 12, 15 minutes. If they start tolling together, after who
will they next toll together?​

Answer 1

Answer:

Can fuo numbers have 16 as their HCF and 204 as thetr LCM? Glue red

We know that the HCF of two or more numbers must divide their LOM

Souton

4. 36, 60,72

8. 144.180,3

Mathematics for Clasa 6

19. The HCF of two numbers is 145 and their LCM is 2175. If one of the numbers is 72%

20. The HCF and LCM of two numbers are 131 and 8253 respectively. If one of the num

22. Find the least number which when divided by 25, 40 and 60 leaves 9 as the remaine

We know that

(one number) x (the other number) = (HCF X LCM).

Hence, the required number =

23 1449

161

- 207

EXAMPLE 10

Solution

But, 16 does not divide 204 exactly

So, there can be no two numbers with 16 as their HCF and 204 as the

EXERCISE 2E

Find the LCM of the numbers given below:

1. 42. 63

2. 60, 75

3. 12, 18, 20

5. 36, 40, 126

6. 16. 28, 40, 77 7. 28, 36, 45, 60

48. 64, 72, 96, 108

Find the HCF and LCM of

10. 117, 221

11. 234, 572

12. 693, 1078

14. 861, 1353

15. 2923, 3239

16. For each pair of numbers, verify that their product (HCF X LCM).

(1) 87, 145

(ii) 186, 403

(ii) 490, 1155

17. The product of two numbers is 2160 and their HCF is 12. Find their LCM.

18. The product of two numbers is 2560 and their LCM is 320. Find their HCF.

the other.

917, find the other.

21. Find the least number divisible by 15, 20, 24, 32 and 36.

1353

13. 145, 232

each case.

Answer 2

Can’t understand the question