can here some one here have tallented mind
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This is a velocity-time graph. Its slope will give acceleration.
OA gives increasing acceleration. Hence this is increasing velocity with respect to time i.e linear and accelerated motion.
AB has no slope. Hence there is no acceleration. The body is moving at constant velocity. The motion is un-accelerated.
BC has negative slope. The motion is decelerated. Velocity is decreasing.
Velocity at point A= 10m/s
Velocity at point B= 10m/s
Velocity at point C= 0m/s
Acceleration at OA= 10-0/4-0s 2.5m/s⁻²
Acceleration at AB= 10-10/10-4=0m/s⁻²
Acc at BC= 0-10/14-10= -10/4= -2.5 m/s⁻²
Distance travelled in BC= v²= u²+ 2as
0²= 10²+ 2(-2.5)s
-100=-5s
s= 20 metres
OA gives increasing acceleration. Hence this is increasing velocity with respect to time i.e linear and accelerated motion.
AB has no slope. Hence there is no acceleration. The body is moving at constant velocity. The motion is un-accelerated.
BC has negative slope. The motion is decelerated. Velocity is decreasing.
Velocity at point A= 10m/s
Velocity at point B= 10m/s
Velocity at point C= 0m/s
Acceleration at OA= 10-0/4-0s 2.5m/s⁻²
Acceleration at AB= 10-10/10-4=0m/s⁻²
Acc at BC= 0-10/14-10= -10/4= -2.5 m/s⁻²
Distance travelled in BC= v²= u²+ 2as
0²= 10²+ 2(-2.5)s
-100=-5s
s= 20 metres
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