can i get derivation of this
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Newton’s second law of motion states that: the net external force applied on an object is directly proportional to the rate of change of linear momentum of the object.
Let the external force be F, initial velocity be u ,final velocity be v, the time interval be t.
=> p1(initial momentum ) = mu
p2(final momentum )= mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s IInd law , F α Δp
=>F =k * (mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
=> F = ma
Hence proved
Newton’s second law of motion states that: the net external force applied on an object is directly proportional to the rate of change of linear momentum of the object.
Let the external force be F, initial velocity be u ,final velocity be v, the time interval be t.
=> p1(initial momentum ) = mu
p2(final momentum )= mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s IInd law , F α Δp
=>F =k * (mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
=> F = ma
Hence proved
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i hope this answer helps you
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farheen2019:
thankyou so much karthikashok
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