can I get the answer for both the question with steps pls
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heya....ur answer is in attachment. ...
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Anonymous:
kyu kya hua
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a+b+c=0
a^3+b^3+c^3= (a+b+c)(a^2+b^2+c^2-ab-bc-ca) +3abc
=0+3abc
=3abc
a^3+b^3+c^3= (a+b+c)(a^2+b^2+c^2-ab-bc-ca) +3abc
=0+3abc
=3abc
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