Question

Can I get the answer for the attached question please?

Answer 1

Answer:

Step-by-step explanation:

In triangleAPO and QDO

AngleAPO=angleDPO

angleAOP=angleDOQ

So by AA ∆APO=~∆DQO

BY CPCT AP=DQ -1

BUT AP=PB

And DQ=CQ

soPB=CQ -2

From 1 and 2

AP+PB=DQ+CQ

=> AB=CD

Hence proved