Question

Can i get the answer for the below question? Please

Answer 1

Answer:

ANGLE ATB = 80 (given)

In triangle ABT

TB=TA (tangents draw from an external point to the circle are equal in length0)

ANGLE ABT = ANGLE TAB(angles opposite to equal sides of an isosceles triangle) - equation 1

ANGLE ABT + ANGLE TAB + ANGLE ATB = 180 (angle sum property of a triangle)

2*ANGLE ABT + 80= 180 (From equation 1 and given)

2*ANGLE ABT = 100

ANGLE ABT = 100/2

ANGLE ABT = 50