Can i get the answer for this trigonometric question please.
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Step-by-step explanation:
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Answered by
2
Step-by-step explanation:
LHS
tan-cot/sincos=sin/cos-cos/sin/sincos
=sin²-cos²/(sincos)²
=sin²-cos²/sin²cos²
RHS
tan²-cot²=sin²/cos²-cos²/sin²
So,
sin⁴-cos⁴/sin²cos² ...so now (a²)²-(b²)²=a²+b²×a²-b²
= (sin²-cos²)(sin²+cos²)/sin²cos²...since sin²+cos²=1..
=sin²-cos²/sin²cos²
So ,
LHS=RHS
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