can I get the full solution
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sweety70:
width is decreased by 1 or 4m?
Answers
Answered by
3
Hi !
Let ,
Breadth = x
Then ,
Length = y
Given ,
y = 2x - 7
2x - y = 7 ---> [1]
=======================
Perimeter = 2(length+ breadth) = 66 m
new length :-
y-1
new breadth= x - 4
2(y-1 + x - 4) = 66
2(y + x -5) = 66
2y + 2x -10 = 66
2x + 2y = 76
2(x+y) = 76
x + y = 76/2
x + y = 38 ----> [2]
adding equations 1 and 2 ,
x + y = 38
2x -y = 7
=========
3x = 45
x = 45/3
= 15
x + y = 38
15 +y = 38
y = 38 - 15
= 23
Length = y = 23 m
Breadth = x = 15 m
Let ,
Breadth = x
Then ,
Length = y
Given ,
y = 2x - 7
2x - y = 7 ---> [1]
=======================
Perimeter = 2(length+ breadth) = 66 m
new length :-
y-1
new breadth= x - 4
2(y-1 + x - 4) = 66
2(y + x -5) = 66
2y + 2x -10 = 66
2x + 2y = 76
2(x+y) = 76
x + y = 76/2
x + y = 38 ----> [2]
adding equations 1 and 2 ,
x + y = 38
2x -y = 7
=========
3x = 45
x = 45/3
= 15
x + y = 38
15 +y = 38
y = 38 - 15
= 23
Length = y = 23 m
Breadth = x = 15 m
Answered by
3
Heya,
Let the width of of the rectangle be x and length be y
Given,
Y= 2x-7-------------(1)
Length is decreased by 1 and Width is decreased by 4
⇒ Y -1 and x- 4
Perimeter = 2(l+b)
⇒66 = 2 ( y-1+x-4)
66= 2(x+y-5)
33 = x+y -5
x + y = 38---(2)
Substitute eq (1) in eq (2)
x+2x-7 = 38
3x = 45
x= 45/3
x = 15
Substitute vale of x in eq(2)
15 +y = 38
y = 23.
Therefore length of the rectangle is 23 m and width is 15 m.
Hope it helps u.....
Let the width of of the rectangle be x and length be y
Given,
Y= 2x-7-------------(1)
Length is decreased by 1 and Width is decreased by 4
⇒ Y -1 and x- 4
Perimeter = 2(l+b)
⇒66 = 2 ( y-1+x-4)
66= 2(x+y-5)
33 = x+y -5
x + y = 38---(2)
Substitute eq (1) in eq (2)
x+2x-7 = 38
3x = 45
x= 45/3
x = 15
Substitute vale of x in eq(2)
15 +y = 38
y = 23.
Therefore length of the rectangle is 23 m and width is 15 m.
Hope it helps u.....
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