Question

can I get the full solution

Answer 1

the four integers will be 11,13,15,17

Answer 2

Let the 1st number be x
X+2 be the second
X+4 be the third
X+6 be the fourth
(X)+(x+2)+(x+4)+(x+6)=56 combine similar terms.
X+X+X+X=56-2-4-6
4X=44 divide both side by 4 to get X
X=44/4
X=11
(X+2)=(11+2)=13
Therefore 13 is second number
(X+4)=(11+4)=15
Therefore 15 is third number
(X+6)=(11+6)=17
Therefore 17 is fourth number
The four consecutive numbers are 11 13,15,17
11+13+15+17=56

Hope this helps you!