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The orthocenter of the triangle formed by (0,0),(8,0),(4,6) is
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Correct option is A)
Let ABC be the given triangie and the vertices be A(0,0),B(8,0) and C(4,6).
∵ Slope of BC=
(4−8)
(6−0)
=−
2
3
.
∴ Equation of line through A and ⊥ to BC is
y−0=(
3
2
)(x−0)⇒2x−3y=0 ...(1)
And slope of CA=
(4−0)
(6−0)
=
2
3
∴ Equation of line through B and ⊥ to CA is
y−0=(−
3
2
)(x−8)⇒2x+3y=16 ...(2)
Solving (1) and (2), the orthocentre is (4,
3
8
).
Answered by
0
Answer:
9
Step-by-step explanation:
Orthocentre = (x1 + x2 + x3)/3, (y1 + y2 + y3)/3
= 10/3, 8/3
=> h = 10/3
k = 8/3
3(h + k)/2
= 3(10 + 8)/3 x 1/2
= 18/2
= 9
Hope it helps :)
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