Math, asked by reenasingh4978, 1 month ago

Can I have answer to this?
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Answered by Saby123
2

Solution :

 \displaystyle \bold \sf \dfrac{ 4x + 1}{3} + \dfrac{ 2x - 1}{ 2} - \dfrac{ 3x - 7}{ 5} = 6 \\ \\ \implies \dfrac{ 10( 4x +1) + 15( 2x -1) - 6( 3x - 7) }{ 30} = 6 \\ \\ \implies \dfrac{ 40x + 10 + 30x - 15 - 18x + 42 }{30} = 6 \\ \\ \implies 52x + 37 = 180 \\ \\ \implies x = \dfrac{ 143 }{ 52} \\ \\ \implies x = \dfrac{ 11 }{ 4 }

 \\ \\ \displaystyle \bold \tt \dfrac{ 2 - 9z }{ 17 - 4z } = \dfrac{ 4}{ 5} \\ \\ \implies 4( 17 - 4z ) = 5( 2 - 9z ) \\ \\ \implies 68 - 16z = 10 - 45z \\ \\ \implies 61z = 58 \\ \\ \implies x = \dfrac{ 51}{ 61}

Answered by regan20072000
1

Answer:

LCM of 3, 2, 5 is 30\\10(4x+1) + 15(2x-1)-6(3x-7)=180\\40x+10+30x-15-18x+42=180\\52x=180-37=143\\x=143/52\\\\2. \\coss multiplying\\10-45z=68-16z\\45z-16z=10-68\\29z=-58\\z=-58/29=-2

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