Can I please get the answer to the above indices sum
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Brainly100:
Hope it helps...
Have i explain correctly?
yes you have thanks a lot mate!
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write 9 as 3 cube and multliply the powers
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Hii friend thanks for asking this question...
Soulution ::--
(3^n × 9^n+1)/(3^n-1×9^n-1)
《= converting 9^m in to (3^2)^m=3^2m》
=3^n × (3^2)^n+1/ 3^n-1 × (3^2)n-1
= 3^n × 3^2n+2 / 3^n-1 × 3^2n-2
= 3^(n+2n+2) / 3^(n-1+2n-2)
= 3^(3n+2) / 3^(3n-3)
= 3^(3n +2 - 3n +3)
= 3^(5-n) .... ANS ....
RULES USED....
A^m × A^n = A^(m+n)
A^m / A^n = A ^( m-n)
HOPE IT HELPS YOU A LOT....
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