Can I use this method for derivation of kynetic energy in class 9 exam
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Consider an object with mass m, moving with initial velocity u. Let a force F, act on it causing a displacement s, along the direction of force and accelaration. Let the object attain final velocity v.
We know F = m x a ------------------------ 1
By position velocity relation we have,
V2 = u2 + 2as or s = v2 -u2 / 2a ----------------------------- 2
The work done by the force
W = F x s -------------------------------------3
Substituting 1 and 2 in
3W = (m x a) x (v2 - u2/2a)
W = m/2 (v2 - u2)W
= 1/2 mv2 - 1/2 mu2 -------------------- 4
For an object to be at rest in the beggining, u = 0
Therefore,
W = 1/2 mv2
W = Ek ( Ek = kinetic energy)
Therefore, Ek = 1/2 mv2
Better to solve like this...
smrutidesai:
But can I solve with that method
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yes you can use this method!!!!!!
it's your wish.
v(=∩_∩=)フ
it's your wish.
v(=∩_∩=)フ
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