can man bought two computers for Rs 45000 he sold one at a loss of 5% and the other at profit of 5% if the selling price of each set is same so find the cost price of each set
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Given :
A man bought two computers for rs 45000. he sold one at a loss of 5% and other at a profit of 5%. The selling price of each set is the same.
To find :
find the cost price of each set.
Solution :
Let the cost price of one computer be x
The second computer be ( 45000-x)
Selling price :
he sold one at a loss of 5%:
100 - 5 = 95.
Loss on CP = 95x/100
He sold others at a profit of 5%:
100 + 5 = 105
Profit on CP = (45000-x)*105/100
Cost Price :
Given : Selling price is same for each computer:
=> 95x/100 = (45000-x)*105/100
=> 95x/100 = (45000 * 105)/100 - 105x/100
=> 95x/100 = 47250 - 105x/100
=> 95x/100 + 105x/100 = 47250
=> 200x/100 = 47250
=> 2x = 47250
=> x = 47250/2
=> x = 23625
So, the cost of first computer is Rs 23,625
The cost of second computer is 45000 - 23625 = Rs 21,735.
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