can ne 1 solve this problem
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ANURAGSETH20:
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I have proved it .
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mark my answer as brainlist
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given
let ABC is a right angle triangle
BD divides the right angle triangle into two equal parts
consider triangle ABD, triangle BDC
AB = BC
AD = CD
BD = BD ( common )
there for triangle ABD ~= triangle BDC
D is the mid point of AC
BD is half of the right angle triange
BD = 1/2 AC
let ABC is a right angle triangle
BD divides the right angle triangle into two equal parts
consider triangle ABD, triangle BDC
AB = BC
AD = CD
BD = BD ( common )
there for triangle ABD ~= triangle BDC
D is the mid point of AC
BD is half of the right angle triange
BD = 1/2 AC
how is ab = ac
sry ab= bc
ab is not equal to bc
it is equal
AB = BC
once see clear
when mid point divided the right angle triangle so the mid point is the half of the triangle
so how is base equals to other side
ones take a right angle triangle and fold it
you you write ABC and mid point B opposite D
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