Question

©An object 5 cm in height is placed at a distance 20 cm in front of convex mirror of radius of curvature is 30cm. Find the position of image , its nature and size

# 10points

#thanks

Answer 1

Hey there !!!!

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Object distance = 20cm  

Using sign conventions u = -20cm

Radius of curvature = 30cm = R

R =2f

f= R/2 = 15cm

Focal length = 15cm 

Using sign conventions  focal length = -15cm

Using mirror formula

1/v+1/u=1/f

1/v= 1/f-1/u

1/v = -1/15-1/(-20)

1/v = -1/15+1/20

1/v = -4+3/60

1/v = -1/ 60 

v =-60cm

Image is formed beyond focal point and Center of curvature so image is "real"

Magnification  = -v/u = -(-60)/-20 = -3

-3= Height of image / Height of object 

-3 = Height of image / 5

Height of image = 15cm 

Negative sign indicates image is inverted

So image formed is real, inverted and height of image = 15cm

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Hope this helped you...............

Answer 2

Answer:

Explanation:

20 cm