Math, asked by ushapatil1502, 5 months ago

can please any one answer my question​

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Answered by prajinraj31
0

Answer:

this seems tough

so i think icant help u im sarry

Answered by nandanaMK
3

\huge\red{\underline{Question}}

y -  \frac{y - 1}{2}  =  \frac{1 - y - 2}{3}

\huge\red{\underline{Answer}}

 \frac{y}{1}  -  \frac{y - 1}{2}  =  \frac{1 - y - 2}{3}

 \frac{y \times 2}{1 \times 2}  -  \frac{y - 1}{2}  =  \frac{1 - y - 2}{3}

 \frac{2y}{2}  -  \frac{y - 1}{2}  =  \frac{1 - y - 2}{3}

 \frac{2y - (y - 1)}{2}  =  \frac{1 - y - 2}{3}

 \frac{2y - y + 1}{2}  =  \frac{1 - y - 2}{3}

 \frac{y + 1}{2}  =  \frac{1 - y - 2}{3}

3 \times (y + 1) = 2 \times (1 - y - 2)

3y + 3 = 2 - 2y - 4

3y + 2y = 2 - 4 - 3

5y =  - 5

y =  \frac{ - 5}{ \:  \:  \: 5 }

y = ( - 1)

 \large \boxed{Solution \:  \:  of  \:  \: this  \:  \: equation \:  \:  is \:  \:  y = (-1).}

 \purple{Hope \:   \: this \:   \: helps  \: \:  you \: !}

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